In particular, have a lemma Forall2_cons that is an ↔.
Forall2_cons
↔
For consistency, rename Forall2_cons_inv to Forall2_cons_1 (matching Forall_cons_1).
Forall2_cons_inv
Forall2_cons_1
Forall_cons_1
Someone should probably do the same for Forall3...
Forall3
00:04:39
3 years ago
No artifacts found
00:04:53
00:04:45